Question

Jordan and Roman travel the same route to work. Jordan leaves for work one morning and drives at a rate, r, of 56 mph. Roman leaves the house soon after, when Jordan has already traveled 2 mi. Roman drives at a rate of 60 mph. How long after Jordan leaves home will Roman catch up to her? How many miles into their commute will this occur?Which system of equations models this problem?

Answer 1

Answer:

d = 56t

d = 60t – 2

Step-by-step explanation:

D= Distance T=time    d = 56t (Jordan)   d = 60t - 2 (Roman)

d = 56t   d = 60t - 2    

56t = 60t - 2            d = 56(1/2)      d = 60(1/2) - 2

-60t  -60t                 d = 28             d = 30 - 2 = 28

-4t = -2

t = 1 / 2

Answer 2

The equations are d = 56t and d = 60t - 2 and the distance which they travel will be 30 miles.

What is speed?

The distance covered by the particle or the body in an hour is called speed. It is a scalar quantity. It is the ratio of distance to time.

We know that the speed formula

$\rm Speed = \dfrac{Distance}{Time}$

Jordan and Roman travel the same route to work.

Jordan leaves for work one morning and drives at a rate of 56 mph.

Then the distance traveled by the Jordon will be

d = 56t  .....(1)

Roman leaves the house soon after when Jordan has already traveled 2 miles.

Roman drives at a rate of 60 mph.

Then the distance covered by the Roman will be

d = 60t - 2 .....(2)

Then from equations 1 and 2, we have

  60t - 2 = 56t

60t - 56t = 2

          4t = 2

            t = 0.5

Then the distance traveled will be

d = 60 (0.5)

d = 30 miles

More about the speed link is given below.

https://brainly.com/question/7359669