Question

1.A solution has a volume of 2500 mL. How
many liters is this?
2. Convert 50 g of calcium carbonate, CaCO3,
into moles.
3. A solution contains 0.42 moles of solute in
0.75 L. Calculate the molarity of the solution.
4. What is the molarity of a solution that contains
15.0 g of NaOH per 500.0 mL of solution?
5. A 250.0 mL solution contains 4.6 g of copper
(II) chloride, CuCl2. Find the molarity of this
solution.
6. How many moles of hydrochloric acid, HCl, are
present in 0.085 L of a 3.0 M solution?
7. A 37.5 mL solution contains 0.181 g of
potassium chromate, K2CrO4. What is the
molarity?
8. What is the molarity of a solution that contains
0.85 g of ammonium nitrate, NH4NO3, dissolved
in a solution with volume 100.0 mL?
9. Calculate the mass of lead (II) nitrate, Pb(NO3)2,
necessary to make 50.0 mL of a 0.100 M solution.
10. What volume of a 0.35 M solution of sodium
chloride could be formed with 25 g of NaCl?

Answer 1

Answer:

2.5litres

0.0005moles

0.56M

0.75M

0.1369M

0.255moles

0.0163M

0.10625M

3.312g

1221.14cm³

Explanations

1. 25÷1000=2.5l

2.Moles=Mass÷RFM

50÷1000÷(100)

0.0005moles

3.I litre=1000cm³

0.75litres=?

750cm³

0.42moles=750cm³

?=1000cm³

0.56M

4. Molarity=Conc. in g/l÷RFM

Conc.g/l

15g=500cm³

1000cm³

30g/l

Molarity

30÷(23+16+1)

0.75M

5.4.6g=250cm³

1000cm³

18.4g/l

Molarity

18.4÷(134.446)

0.1369M

6.3moles=1000cm³

(0.085×1000)

0.255moles

7.Conc.g/l

37.5cm³=0.181g

1000cm³

4.827g/l

Molarity=4.827÷(296)

0.0163M