Question

The archway of the main entrance of a university is modeled by the quadratic equation y = -x2 6x. the university is hanging a banner at the main entrance at an angle defined by the equation 4y = 21 − x. at what points should the banner be attached to the archway?

Answer 1

The banner attached to the archway will be at (1, 5) and (5.25, 3.938).

What is the parabola?

It's the locus of a moving point that keeps the same distance between a stationary point and a specified line. The focus is a non-movable point, while the directrix is a non-movable line.

The archway of the main entrance of a university is modeled by the quadratic equation

y = -x² + 6x ....1

The university is hanging a banner at the main entrance at an angle defined by the equation

4y = 21 − x ....2

Then the banner attached to the archway will be

From equations 1 and 2, we have

              4(-x² + 6x) = 21 - x

              -4x² + 24x = 21 - x

        4x² - 25x + 21 = 0

  4x² - 21x - 4x + 21 = 0

x(4x - 21) - 1(4x - 21) = 0

          (4x - 21)(x - 1) = 0

                             x = 5.25, 1

Then the value of y will be

When x = 5.25, then we have

y = -(5.25)² + 6(5.25)

y = 3.938

When x = 1, then we have

y = -(1)² + 6(1)

y = 5

The banner attached to the archway will be at (1, 5) and (5.25, 3.938).

The graph is given below.

More about the parabola link is given below.

https://brainly.com/question/8495504

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