Answer:
x = [tex]-\frac{1}{9}[/tex]
Step-by-step explanation:
FOIL what is in the parentheses by multiplying terms by -4.
[tex]-4(3x+\frac{2}{6})[/tex]
-4(3x) = -12x and -4(2/6) = -4/3
now add these products: [tex]-12x-\frac{4}{3}[/tex]
That is the simplified product ^, but assuming you're supposed to set the equation to equal 0...
Set equation to 0 and add the fraction to both sides. Rewrite as [tex]-12x=\frac{4}{3}[/tex]
Divide both sides by -12 to get variable, x, alone. Multiplying 4/3 by -1/12 is the same as dividing 4/3 by -12. The negative sign from the -12 make the quotient negative.
x = [tex]-\frac{1}{9}[/tex]
Answer:
x = -1/9
Step-by-step explanation:
FOIL what is in the parentheses by multiplying terms by -4.
-4(3x) = -12x and -4(2/6) = -4/3
now add these products:
That is the simplified product ^, but assuming you're supposed to set the equation to equal 0...
Set equation to 0 and add the fraction to both sides. Rewrite as
Divide both sides by -12 to get variable, x, alone. Multiplying 4/3 by -1/12 is the same as dividing 4/3 by -12. The negative sign from the -12 make the quotient negative.
x= 1/9
