Question

What volume of 12M HCI is needed to prepare 250
of 0.20M HCI?

Answer 1

Answer: 4.2

Explanation:

$M_{A}V_{A}=M_{B}V_{B}\\(12)V_{A}=(250)(0.20)\\V_{A}=\frac{(250)(0.20)}{12}=\boxed{4.2}$