Question

7. Write the equation for the positron emission of barium-127.

Answer 1

The reaction is given by

$\\ \rm\Rrightarrow {}^{127}_{56}Ba\longrightarrow {}^{0}_{+1}\beta+{}^{127}_{55}Cs$

Barium goes underneath beta decay to form Ceaseum

• Cs is very mellable element
• It can melt on your hand

Answer 2

$\sf {}^{127}_{56}Ba\longrightarrow {}^0_{1}\beta+{}^{127}_{55}Cs$

Remember

• Radioactive decays are first order reactions
• The rate constant doesn't depend upon initial concentration
• It's never ending reaction