The molarity of the solution given the data from the question is 0.0135 M
Molarity is simply defined as the mole of solute per unit litre of solution. Mathematically, it can be expressed as:
Molarity = mole / Volume
Mole = mass / molar mass
Mole of MgSO₄ = 1.78 / 120.4
Mole of MgSO₄ = 0.0148 mole
Molarity = mole / Volume
Molarity = 0.0148 / 1.1
Molarity = 0.0135 M
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