Question

What is limit of startroot x squared minus 8 endroot as x approaches negative 3? –5 1 startroot 2 endroot startroot negative 14 endroot

Answer 1

The limit of $\lim_{x \to -3}\sqrt{ x^2-8}$ as x approaches negative 3 is 1

Limit of a function

The limit of the function given in question can also be written as:

$\lim_{x \to -3}\sqrt{ x^2-8}$

To determine the required limit, we will simply substitute the value of x into the function as shown:

$\lim_{x \to -3}\sqrt{ x^2-8}=\sqrt{ (-3)^2-8}\\\lim_{x \to -3}\sqrt{ x^2-8}=\sqrt{9-8}=1$

Hence the limit of $\lim_{x \to -3}\sqrt{ x^2-8}$ as x approaches negative 3 is 1

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