Question

31. calculate the amount of energy released as heat by the freezing of 13.3 g of a liquid substance, given that the substance has a molar mass of 82.9 g/mol and a molar enthalpy of fusion of 4.60 kj/mol.

Answer 1

From the calculations, the heat of fusion of the substance is 0.73 kJ

What is is the heat of freezing?

The heat of freezing is the energy released when the substance is converted from liquid to solid.

Now we know that the molar mass of the substance is 82.9 g/mol  hence the number of moles of the substance is;  13.3 g /82.9 g/mol  = 0.16 moles

Now the heat of fusion shall be;

H = 4.60 kj/mol * 0.16 moles

H = 0.73 kJ

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