The expanded form of V(x) = x(9-2x) (11-2x) is V(x) = 4x^3 - 20x^2 + 99x
The missing information in the question is to express V(x) in standard form
We have:
V(x) = x(9-2x) (11-2x)
Open the brackets
V (x) = x(99 - 2x - 18x + 4x^2)
Evaluate the like terms
V (x) = x(99 - 20x + 4x^2)
Expand
V (x) = 99x - 20x^2 + 4x^3
Rewrite as:
V(x) = 4x^3 - 20x^2 + 99x
Hence, the expanded form of V(x) = x(9-2x) (11-2x) is V(x) = 4x^3 - 20x^2 + 99x
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