Answer:
a. {(0, 7), (-1, 6)}
Step-by-step explanation:
[tex]y = x^{2} +2x+7\\y=x+7[/tex]
subtract the equations
[tex]y = x^{2} +2x+7 \\- \ \ \ \ \ y=x+7\\y - y =x^{2} +2x+7-(x+7)\\0=x^{2} +x\\x = 0 \ and \ x= -1[/tex]
for [tex]y = x^{2} +2x+7[/tex], substitute x = 0
[tex]y = (0)^{2} +2(0)+7\\y = 0 +0+7\\y=7[/tex]
for [tex]y = x^{2} +2x+7[/tex], substitute x = 0
[tex]y = (-1)^{2} +2(-1)+7\\y = 1 -2+7\\y=6[/tex]