Question

Question 8: The equation of motion of a particle is

s = t^3 4t^2 + 2t + 8
Where s is in meters
and t is in seconds

Find the acceleration after t=5 seconds.

Answer 1

Answer:

D) $22\:\text{m/s}^2$

Step-by-step explanation:

Acceleration is the derivative of velocity, which is the derivative of position, so we must differentiate the function twice:

Position of Particle: $s(t)=t^3-4t^2+2t+8$

Velocity of Particle: $v(t)=3t^2-8t+2$

Acceleration of Particle: $a(t)=6t-8$

After $t=5$ seconds, the acceleration of the particle is $a(5)=6(5)-8=30-8=22\:\text{m/s}^2$