Question

How many grams of aluminum chloride can be produced from 7.32g of ammonium perchlorate?

Answer 1

Answer:

2.77g of $AlCl_{3}$ can be produced.

Explanation:

Use stoichiometry.

Balanced equation: $3Al + 3NH_{4} ClO_{4}$ ⇒ $Al_{2} O_{3} + AlCl_{3} +3NO + 6H_{2} O$

$NH_{4} ClO_{4} : AlCl_{3}$

      3        :     1                        **$n=\frac{m}{M}$

 0.0623**   :    $x$                        $n=\frac{7.32}{117.49}$   = 0.0623

      $3x=0.0623\\x=0.020767$

$n=\frac{m}{M}$    

$m=nM$

m= (0.020767)(133.34)

m= 2.77g