The distance between library and park is 6√2 miles and the distance between park and field is 6√11 miles.
Similar triangles are the triangles that have corresponding sides in proportion to each other and corresponding angles equal to each other.
Here, mark the park as A, Home as B, Library as C and field as D.
Now, CD = 18 miles
BC = 4 miles
we have to find AC (distance between library and park)
BD = BC + CD = 18 + 4 = 22 miles
Using property of similar triangles,
AD² = BD X CD
AD² = 22 X 18
AD = √22 X √18
AD = 6√11 miles
By Pythagoras theorem,
AD² = AC² + CD²
396 = AC² + 324
AC² = 396 - 324
AC² = 72
AC = √72
AC = 6√2 miles
Thus, the distance between library and park is 6√2 miles and the distance between park and field is 6√11 miles.
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