Given that the linear expansion of the pipe is 12×10¯⁶ K¯¹, the pipe extends by 0.024 mm
α = ΔL / L₁ΔT
12×10¯⁶ = ΔL / (100 × 20)
12×10¯⁶ = ΔL / 2000
Cross multiply
ΔL = 12×10¯⁶ × 2000
ΔL = 0.024 mm
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