1.The temperature will be, T2= 169.8 K
2. The volume if the temperature is 318 K is 0.170 L
Charles's law, a statement that the volume occupied by a fixed amount of gas is directly proportional to its absolute temperature, if the pressure remains constant.
Given: V1= 250 ml=0.25L
V2=150 ml= 0.15 L
T1= 10 °C=283 K, T2=?
Now using Charles law
V1/T1=V2/T2
0.25/283=0.15/T2
T2= 169.8 K
2. T1= 20 °C= 293 K
V1= 160 cm³
T2= 318 K
V2=?
Using Charles Law,
V1/T1=V2/T2
0.16/293=V2/313
0.170 L=V2
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