a) If you’re heading due North, total acceleration will be 0.0478 m/s².
b) If you’re heading due East, acceleration will be 0.0803 m/s².
c) If you’re heading straight up, no exact value for acceleration.
The time rate of change of velocity is known as acceleration.
a)If the boat is going along North from equator, there will be only centrifugal force acting along upward direction which will be balanced by the weight of boat.
Angular velocity ω= (2π / (3600 x 24)) = 7.27 x 10⁻⁵ rad/s
Acceleration due to centrifugal force a = 0.0337m/s²
Centrifugal force due to its own velocity 300 m/s is v²/r = 0.0141 m/s².
Total acceleration will be 0.0141 +0.0337 =0.0478m/s².
Thus, if you’re heading due North, total acceleration will be 0.0478 m/s².
b) If the boat goes along East, Coriolis acceleration is in the direction of centrifugal force.
Coriolis acceleration is (2 x 7.27 x 10⁻⁵ x300 ) = 0.0436m/s².
Total centrifugal acceleration due to centrifugal force = 300 + (7.27 x 10⁻⁵ x 6371 x 10³) = 0.0436 m/s².
Total acceleration is 0.0436 + 0.0367 = 0.0803m/s².
Thus, if you’re heading due East, acceleration will be 0.0803 m/s².
c) When boat is going upward, centrifugal force will change with time. but Coriolis acceleration remains same.
Thus, if you’re heading straight up, no exact value for acceleration.
Learn more about acceleration.
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