Question

pls help! thank you!

Answer 1

Using the zero product property, we can set each factor equal to zero.

First Factor $x^{4}+5x^{2}-36$

$x^{4}+5x^{2}-36=0\\(x^{2}+9)(x^{2}-4)=0\\x^{2}+9=0, x^{2}-4=0\\x=\pm 3i, x=\pm 2$

Second Factor $2x^{2}+9x+5$

Using the quadratic formula, we get $x=\frac{-9 \pm \sqrt{41}}{4}$.