Answer:
h(j+1) = 4j² +11j +5
Step-by-step explanation:
A function is evaluated for a specific argument by substituting that argument for the variable in the function's expression. Then the expression is simplified.
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For function ...
h(x) = 4x² +3x -2
The value of h(j+1) is ...
[tex]h(j+1)=4(j+1)^2 +3(j+1)-2\\\\= (4(j+1)+3)(j+1)-2=(4j+7)(j+1)-2=4j^2+11j+7-2\\\\\boxed{h(j+1)=4j^2+11j+5}[/tex]
