Question

The length of a rectangle 3yd is less than twice the width, and the area of the rectangle is 14yd^2. Find the dimensions of the rectangle.

Answer 1

Answer: 4 yd x 3.5 yd

Step-by-step explanation:

A = LW

L = 2x - 3

W = x

14 = (2x - 3)(x)

14 = 2x^2 - 3x

2x^2 - 3x - 14 = 0

(x + 2)(2x - 7)

x = - 2, 7/2 or 3.5 (length cannot be negative)

x = 3.5 (width)

Length

2x - 3

2(3.5) - 3

7 - 3 = 4

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