Question

35.0g of zinc oxide react with what volume of oxygen at stp given the following reaction: zn + o2 --> zno

Answer 1

The volume of oxygen that would react at STP will be 6.00 L

Stoichiometric calculation

From the equation of the reaction:

$2Zn + O_2 --- > 2ZnO$

The mole ratio of $O_2$ to the ZnO produced is 1:2

Mole of 35 g Zn = 35/65.3 = 0.536 moles

Equivalent mole of  $O_2$ that will react = 0.536/2 = 0.268 moles

1 mole of gas at STP = 22.4 L

0.268 moles of gas = 0.268 x 22.4 = 6.00 L

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