CAN SOMEONE HELP ME PLS?

Triangle [tex]\triangle ABC[/tex] and triangle [tex]\triangle DEC[/tex] are similar because they have 2 congruent angles. We can find the scale factor between them by comparing the length of [tex]\overline{BC}[/tex] and [tex]\overline{EC}[/tex] in a fraction, resulting in us finding the scale is 3:1 from [tex]\triangle ABC[/tex] to [tex]\triangle DEC[/tex].

Now we can solve for x using a proportion.

[tex]\frac{3}{1} = \frac{x+22}{x+2}[/tex] | Cross multiply

3x+6 = x+22 | Subtract x from both sides

2x+6 = 22 | Subtract 6 from both sides

2x = 16 | Divide both sides by 2

x = 8

Now we can solve for [tex]\overline{AC}[/tex] and [tex]\overline{CD}[/tex] by substitution.

[tex]\overline{AC}[/tex] = x + 22 = 8 + 22 = 30

[tex]\overline{CD}[/tex] = x + 2 = 8 + 2 = 10

These are your answers

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