Question

A plane and a sphere intersect in a circle that has an area of $48 \pi$. The distance between the plane and the center of the sphere is $3$ units. Find the surface area of the sphere.

Answer 1

The surface area of the sphere based on the information will be 2304π.

How to calculate the area?

It should be noted that the radius of the circle will be 1/2 the length of the line. Therefore, the radius in the shape will be:

= 1/2 × 48

= 24 units.

Therefore, the area of the sphere will be:

= 4πr²

= 4 × π × 24²

= 2304π

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