The distance between a and b is 5 units.
An equilateral triangle has three sides that have the same length. The triangle is defined as the plane two-dimensional figure with three sides having the sum of the three angles of 180 degrees.
Since the figure is missing in the question so I have attached the figure of the points on the graph for better understanding.
The given coordinates are as follows:-
a (-3, 2)
b (-6, -2)
c (0, -2)
Use the distance formula,[tex]d=\sqrt{(x_2-x_1)^2+(y_2-y_1)^2}[/tex] , to find ab.
ab = √[(−6−(−3))² + (−2−2)²]
ab = √25
ab = 5 units
Therefore the distance between A and B is 5 units.
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