Question

Find the
concentration of a sample of sulfuric acid if 25.5 mL of
0.220 M KOH is needed to titrate 20.0 mL of the acid.
M

Answer 1

The concentration of the sulfuric acid will be 0.124 M

Acid-base titration

From the equation of the reaction:

$H_2SO_4 + 2KOH --- > K_2SO_4 + 2H_2O$

The mole ratio of the sulfuric acid to the KOH is 1:2.

Mole of 0.220 M, 22.5 mL KOH = 0.220 x 22.5/1000 = 0.00495 moles

Equivalent mole of the sulfuric acid = 0.00495/2 = 0.002475 moles

Molarity of 20.0 mL 0.002475 moles sulfuric acid = 0.002475/0.02 = 0.124 M

More on calculating molarity can be found here: https://brainly.com/question/15948514

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