Question

A gas occupied 780.0 mL at a temperature of 30°C. Several days later, it was measured at
a temperature of 16°C.
What volume did the gas occupy under these new conditions?

Answer 1

Answer:

744.0 mL

Explanation:

Formula obtained from Charles Law :

⇒ $\frac{V_{1} }{T_{1} } = \frac{V_{2} }{T_{2} }$

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Given :

⇒ V₁ = 780.0 mL

⇒ T₁ = 30 °C = 303 K

⇒ T₂ = 16 °C = 289 K

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Solving :

⇒ V₂ = 780 × 289 / 303

⇒ V₂ = 225420 / 303

⇒ V₂ = 744.0 mL (approximately)