To the nearest thousandth, what is the area of the region bounded by y = ex and x = (y-1)²? 0.089 O 1.188 2.880 4.265

The area bounded by the curves will be 0.089. Then the correct option is A.
When the two curves intersect then they bound the region is known as the area bounded by the curve.
The functions are given below.
y₁ = eˣ ....1
x = (y - 1)² ...2
Then equation 2 can be written as
y₂ = √x + 1
The intersection point of the curves will be
eˣ = √x + 1
BY solving, the value of x will be
x = 0, 0.558
Then the area bounded by the curves will be
[tex]\rm A = \int _0^{0.558} (y_2 - y_1) dx\\\\\\A = \int _0^{0.558} (\sqrt{x} + 1 - e^x )dx\\\\\\A = \left [\dfrac{x^{3/2}}{3/2} + x - e^x \right]_0^{0.558} \\\\\\A = \left [\left (\dfrac{0.558^{3/2}}{3/2} + 0.558 - e^{0.558} \right ) - \left ( \dfrac{0^{3/2}}{3/2} + 0 - e^0 \right) \right]\\[/tex]
On further solving we have
A = -0.911 + 1
A = 0.0887
A ≅ 0.089
Then the correct option is A.
More about the area bounded by the curve link is given below.
https://brainly.com/question/24563834
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