Answer:
The water had no larvae at −10 degrees Celsius and 20 degrees Celsius.
Step-by-step explanation:
We are given the function, [tex]y = -2x^{2} + 20x + 400[/tex]
where
x = temperature of water (in degrees)
y = number of insect larvae in water
What do the x-intercepts of the graph represent?
The x - intercept is when y = 0, and y is the number of insect larvae in the water. So this means there is NO insect larvae in the water.
[tex]y = -2x^{2} + 20x + 400\\0 = -2x^{2} + 20x + 400\\quadratic \ formula:\\\frac{-20 + \sqrt{20x^{2} -4(-2)(400)}}{2(-2)} \\\frac{-20 +\- 60}{-4} \\\frac{-20 + 60}{-4} = -10\\\frac{-20 - 60}{-4} = 20[/tex]
Hence, when there was no larvae in the water, the water temperature was 20 and -10