The time taken for the ball to strike the ground given the data is 3.68 s
Data obtained from the question
- Initial velocity (u) = 18 m/s
- Time to reach the ground (T) =?
How to determine the time to reach maximum height
- Initial velocity (u) = 18 m/s
- Final velocity (v) = 0 m/s (at maximum height)
- Acceleration due to gravity (g) = 9.8 m/s²
- Time to reach maximum height (t) =?
v = u – gt (since the ball is going against gravity)
0 = 18 – 9.8t
Collect like terms
0 – 18 = –9.8t
–18 = –9.8t
Divide both side by –9.8
t = –18 / –9.8
t = 1.84 s
How to determine the time to reach the ground
- Time to reach maximum height (t) =?
- Time to reach the ground (T) =?
T = 2t
T = 2 × 1.84
T = 3.68 s
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