Question

A box of chocolates contains 10 milk chocolates, 8 dark chocolates and 6 white chocolates. Sung randomly chooses a chocolate, eats it, then randomly chooses another. What is the probability Sung chose a milk chololate then a white chocolate

Answer 1

Using it's concept, it is found that there is a 0.1087 = 10.87% probability Sung chose a milk chocolate then a white chocolate.

What is a probability?

A probability is given by the number of desired outcomes divided by the number of total outcomes.

In this problem, we have that:

• Initially, there are 10 + 8 + 6 = 24 chocolates, out of which 10 are milk, hence the probability of eating a milk chocolate first is given by: $\frac{10}{24} = \frac{5}{12}$.

• Then, there will be 23 chocolates, out of which 6 will be white, hence the probability of eating a white chocolate first is given by: $\frac{6}{23}$.

Thus, the probability of milk then white is given by:

$p = \frac{5}{12} \times \frac{6}{23} = \frac{30}{12 \times 23} = 0.1087$

0.1087 = 10.87% probability Sung chose a milk chocolate then a white chocolate.

More can be learned about probabilities at https://brainly.com/question/14398287

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