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By applying definite integrals on the function rate of change, the net change in the deer population between t = 0 and t = 3 is equal to R = - 2,000π.
The net change of a differentiable function in a given interval is equal to the definite integral of the rate of change:
[tex]R(t) = \int\limits^3_0 {r(t)} \, dt[/tex] (1)
If we know that r(t) = 1,000π · cos (0.5π · t), the net change of the function is:
[tex]R(t) = 1,000\pi \int\limits^3_0 {\cos (0.5\pi\cdot t)} \, dx[/tex]
R = 2,000π · (sin 1.5π - sin 0)
R = - 2,000π
By applying definite integrals on the function rate of change, the net change in the deer population between t = 0 and t = 3 is equal to R = - 2,000π.
To learn more on definite integrals: https://brainly.com/question/22655212
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