Question

Jaxon is flying a kite, holding his hands a distance of 3.25 feet above
the ground and letting all the kite's string play out. He measures the
angle of elevation from his hand to the kite to be 24°. If the string from
the kite to his hand is 105 feet long, how many feet is the kite above the
ground? Round your answer to the nearest tenth of a foot if necessary.

Answer 1

Using the slope concept, it is found that the kite is 46.50 feet above the ground.

What is a slope?

The slope is given by the vertical change divided by the horizontal change, and it's also the tangent of the angle of depression.

In this problem:

• The angle is of 24º.

• The vertical change is of 3.5 + x.

• The horizontal change is of 105.

Hence:

tan(24º) = (3.5 + x)/105.

3.5 + x = 105tan(24º)

x = 105tan(24º) - 3.5

x = 43.25 ft.

Hence, the height of the kite is:

43.25 ft + 3.25 ft = 46.50 feet.

More can be learned about the slope concept at https://brainly.com/question/18090623

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