Question

A man is twice as old as sum of ages of his two sons. After ten years the sum of his age and ages of his sons is equal to 105 then present age of man is:

50
60
70
80

Answer 1

The present age  of the man is 70

What are the linear equations that represent the question?

a = 2b equation 1

105 = a + b equation 2

Where:

• a = man's age
• b = sum of his son's age

What is the man's present age?

Substitute for a in equation 2

105 = 2b + b

105 = 3b

3b = 105

b = 35

Substitute for b in equation 1 : a = 2 x 35 = 70

To learn more about simultaneous equations, please check: https://brainly.com/question/25875552

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