Question

the equation of a circle is x^2 + y^2 + 6y=7

Answer 1

Answer:

x = $-3 + \sqrt{(4+x)(4-x)}$

y = $-3 - \sqrt{(4+x)(4-x)}$

Step-by-step explanation:

$x^2 + y^2 + 6y=7$

⇒ $\left(x-a\right)^2+\left(y-b\right)^2$

$\left(x-0\right)^2+\left(y-\left(-3\right)\right)^2 =4^2$

What happened in this math problem:

• We used the standard circle formula to find the properties of the circle as well as its variables.