Question

a 2.00l flask was filled with 4.00 mol of hi at a certain temperature and given sufficient time to react. at equilibrium the concentration of h2 was 0.400 m. find the equilibrium concentrations of i2 and hi and then find the keq at this temperature. 2hi(g) <==> h2(g) + i2(g)

Answer 1

From the calculations and data, the equilibrium constant is 16.

What is equilibrium?

The term equilibrium refers to the state in which the rate of forward reaction and the rate of reverse reaction becomes equal.

Setting up the ICE table

Concentration of HI =  4.00 mol /2.00l  = 2 M

Concentration of H2 and I2 = 0.4 M

Hence;

             2HI <==> H2(g) + I2(g)

I             2             0            0

C            -x           +x            +x

E           2 - x         0.4         0.4

Hence x = 0.4

[HI]eq =

2 - 0.4 = 1.6

Keq = (1.6)^2/(0.4)^2 = 2.56/0.16 = 16

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