“Jonny pulls his sister Jane (weight 28 lbs), who is sitting in a wagon, up an incline ramp (θ = 17°) with a steady speed. If the coefficient of kinetic friction is 0.18, the wagon has a mass of 14 kg, and the length of the ramp is 2.4 m, find: a) the work done by the frictional force. b) the work done by the gravitational force.“

Respuesta :

(a) The work done by the frictional force is -33.1 J.

(b) The work done by the gravitational force is 175.58 J

Work done by frictional force

The work done by frictional force is calculated as follows;

W = -μmgsinθ x L

W = -μmgsinθ  x L

where;

  • m is mass of Jane and wagon

W = -0.18 x (12.7 + 14)9.8 x sin(17) x 2.4

W = -33.1 J

Work done by the gravitational force

W = mgh

W = mgcosθ  x h

W = mgcosθ  x Lsinθ

W = (26.7)(9.8)cos(17) x 2.4 x sin(17)

W = 175.58 J

Learn more about work done here: https://brainly.com/question/8119756

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