By concepts of trigonometry and of perpendicularity, the angles AKL and AKC from respective right triangles have measures of 90° and 32.3°, respectively.
How to find angles by trigonometric relationships
As planes ABCD and BCLK are perpendicular to each other, the triangles AKL and AKC are right angled. The required angles can be found by using the following trigonometric relationships:
[tex]\angle AKL = 90^{\circ}[/tex] (As line segments AK and KL are perpendicular to each other)
[tex]\angle AKC = \tan^{-1} \left(\frac{AC}{KC} \right) = \tan^{-1} \left(\frac{\sqrt{2}\cdot a}{\sqrt{5} \cdot a} \right) = \tan^{-1} \sqrt{\frac{2}{5} }[/tex] (as line segments AC and KC are perpendicular to each other)
[tex]\angle AKC \approx 32.312^{\circ}[/tex]
By concepts of trigonometry and of perpendicularity, the angles AKL and AKC from respective right triangles have measures of 90° and 32.3°, respectively.
To learn more on right triangles: https://brainly.com/question/6322314
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