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What volume of KI solution of concentration of 3 M would use to make 0.3L of KI solution of 1.25 M?

Respuesta :

Taking into account the definition of dilution, a volume of KI solution of 0.125 L of concentration of 3 M would use to make 0.3L of KI solution of 1.25 M.

What is Dilution

When it is desired to prepare a less concentrated solution from a more concentrated one, it is called dilution.

Dilution is the process of reducing the concentration of solute in solution, which is accomplished by simply adding more solvent to the solution at the same amount of solute.

In a dilution the amount of solute does not change, but as more solvent is added, the concentration of the solute decreases, as the volume (and weight) of the solution increases.

A dilution is mathematically expressed as:

Ci×Vi = Cf×Vf

where

  • Ci: initial concentration
  • Vi: initial volume
  • Cf: final concentration
  • Vf: final volume

Initial volume

In this case, you know:

  • Ci= 3 M
  • Vi= ?
  • Cf= 1.25 M
  • Vf= 0.3 L

Replacing in the definition of dilution:

3 M× Vi= 1.25 M× 0.3 L

Solving:

Vi= (1.25 M× 0.3 L)÷ 3 M

Vi= 0.125 L

In summary, a volume of KI solution of 0.125 L of concentration of 3 M would use to make 0.3L of KI solution of 1.25 M.

Learn more about dilution:

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