Select all of the points that lie on the circle with equation?

The easiest way to determine whether the point is on the circle:
⇒ plugging the values into the equation
⇒ then see if the equation holds true
⇒ meaning that the point is on the line
[tex](3-3)^2+(-7+2)^2=25\\(-5)^2=25\\25=25[/tex]<== true
[tex](8-3)^2+(-2+2)^2=25\\5^2=25\\25=25[/tex]<== true
[tex](3-3)^2+(-3+2)^2=25\\(-1)^2=25\\1=25[/tex]<== false
[tex](3-3)^2+(3+2)^2=25\\5^2=25\\25=25[/tex]<== true
[tex](-2-3)^2+(8+2)^2=25\\(-5)^2+10^2\\25+100=25\\125=25[/tex]<== false
Answer: (3,-7), (8,-2), (3,3)
Hope that helps!