The length of the segment DF is 11 units
How to determine the length of DF?
The given parameters are:
ED = 2y + 12
DF = 3y + 8
EF = 25
The length EF is:
EF =ED + DF
This gives
2y + 12 + 3y + 8 = 25
Evaluate the like terms
5y + 20 = 25
Subtract 20 from both sides
5y = 5
Divide by 5
y = 1
Substitute y = 1 in DF = 3y + 8
DF = 3(1) + 8
Evaluate
DF = 11
Hence, the length of DF is 11 units
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