Question

f p(x) = 2x2 – 4x and q(x) = x – 3, what is (p circle q) (x)

Answer 1

Answer:

$2x^{2} - 16x + 30$

Step-by-step explanation:

Here we have to find p(q(x))

q(x) =x -3

we will plug value of q(x) in x of p(x)

p(x) =2x2-4x

p(q(x)) = 2(x-3)2-4(x-3)

= 2(x2-6x+9)-4(x-3)

=2x2-12x+18 -4x+12

$2x^{2} + 16x + 30$