Question

Select the correct answer from each drop-down menu. Graph shows 2 four-sided polygons in the first quadrant of a coordinate plane. First polygon is at A (3, 0), B (1, 0), C (1, 2), and D (3, 2). Second polygon is at A prime (6, 0), B prime (2, 0), C prime (2, 2), and D prime (6, 2). In the figure, polygon ABCD is transformed to create polygon A′B′C′D′. This transformation is a by a factor of .

Answer 1

This transformation of the polygon ABCD to A'B'C'D' is a by a factor of 2

How to determine the scale factor?

The coordinates are given as:

• First polygon: A (3, 0), B (1, 0), C (1, 2), and D (3, 2).
• Second polygon: A' (6, 0), B'(2, 0), C'(2, 2), and D'(6, 2)

Calculate the distance AB and A'B' using:

$d = \sqrt{(x_2 -x_1)^2 + (y_2 -y_1)^2}$

This gives

$AB = \sqrt{(3-1)^2 + (0-0)^2} = 2$

$A'B' = \sqrt{(6-2)^2 + (0-0)^2} = 4$

Divide A'B' by AB to determine the scale factor (k)

k = 4/2

k = 2

Hence, this transformation is a by a factor of 2

Read more about transformation at:

https://brainly.com/question/4289712

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Answer 2

Answer:h-00

Step-by-step explanation:h