The magnitude of the vector sum of 2x and 3y is determined as 3.6 units and the direction is 56.3⁰.
The magnitude of two vectors is determined using the following formula;
[tex]|V| = \sqrt{V_x^2 + V_y^2}[/tex]
Let the sum of the vector = 2x + 3y
The magnitude of the vectors is calculated as follows;
[tex]|V| = \sqrt{2^2 + 3^2} \\\\|V| = 3.6 \ units[/tex]
The direction of the vectors is calculated as follows;
[tex]tan(\theta) = \frac{V_y}{V_x} \\\\tan(\theta) = \frac{3}{2} \\\\tan(\theta) = 1.5\\\\\theta = tan^{-1} (1.5)\\\\\theta = 56.3 \ ^0[/tex]
Thus, the magnitude of the vector sum of 2x and 3y is determined as 3.6 units and the direction is 56.3⁰.
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