15 males and 20 females would maximize the total number of animals
The table is given as:
Males Females Time available
Environment a 20 min 25 min 800 min
Environment b 20 min 15 min 600 min
Represent the male with x and the female with y.
The time available is limited i.e. ≤
So, the constraints are:
20x + 25y ≤ 800
20x + 15y ≤ 600
Solve the above system of inequalities graphically (see attachment)
(x, y) = (15,20)
Hence, 15 males and 20 females would maximize the total number of animals
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