Question

Vector Q is 0.321 m long in a
123° direction. Vector Sis
0.876 m long in a -32.1°
direction.
Find the magnitude of their
vector sum.
magnitude (m)

Answer 1

The magnitude of their vector sum will be 0.60025 m. Law of vector addition is used in given problem.

What is a vector?

A vector is a quantity or phenomena with magnitude and direction that are independent of one another. The phrase also refers to a quantity's mathematical or geometrical representation.

If no vector can be written as a linear combination of the others, a set of vectors is said to be linearly independent.

Angle between Q and S is found as;

θ=123°+32.1°

θ=155.1°

The magnitude of their vector sum,magnitude (m) is found as;

$\rm R = \sqrt{Q^2+S^2+2QS cos \theta } \\\\ R=\sqrt{(0.34)^2+(0.876)^2+2(0.34)(0.870)cos 155.1^0 } \\\\ R=0.6002522 \ m$

Hence,the importance of their vector sum will be 0.60025 m.

To learn more about the vector refer to the link;

https://brainly.com/question/13322477

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