Question

The legs of the base of a right triangular
prism measure 9 in. and 12 in. The prism has
a height of 5 in. What is the surface area of
the prism?

Answer 1

Answer:

the surface area of the prism = 288 in²

Step-by-step explanation:

Let S be the surface area of the prism

     B be the area the base (right-angered triangle)

     L be the lateral surface area

Formula :

S = 2×B + L

……………………

$B=\frac{12\times 9}{2} = 54$

$\text{Length \ of \ the \ third \ side}=\sqrt{12^{2}+9^{2}} =15$

L = 5×(9 + 12 + 15) = 180

S = 2×B + L

S = 2×54+180 = 288 in²