Question

solve for x !
$\bold{4x {}^{2} - 3x + 2 = 0}$

ty! ~​

Answer 1

Step-by-step explanation:

$4 {x}^{2} - 3x + 2 = 0$

We know that,

For the given quadratic equation

$a {x}^{2} + bx + c = 0$

$x = \frac{ - b ± \sqrt{ {b}^{2} - 4ac} }{2a}$

On comparing with the given equation we get

a=4,b=(-3),c=2

On substituting we get,

$x = \frac{ - ( - 3) ± \sqrt{ {( - 3)}^{2} - 4(4)(2)} }{2(4)}$

$x = \frac{3 ± \sqrt{9 - 32} }{8}$

$x = \frac{3 + \sqrt{23}i }{8} or x = \frac{3 - \sqrt{23}i }{8}$

Answer 2

$\large{\underline{\underline{\pmb{\frak {\color {red}{Question:}}}}}}$

$\sf \red{solve \: for \: x}$

$\sf \red{ \bold{4x^{2} - 3x + 2 = 0}}$

$\large{\underline{\underline{\pmb{\frak {\color {blue}{Solution:}}}}}}$

Here,

a = 4, b = - 3 and c = 2

By, using Quadratic formula, we get:

$x = \frac{ - b \pm \sqrt{ {b}^{2} - 4.a.c } }{2.a} \\ \\ = \frac{ - ( - 3) \pm \sqrt{ { (- 3)}^{2} - 4 \times 4 \times 2 } }{2 \times 4} \\ \\ = \frac{3 \pm \sqrt{9 - 32} }{8} \\ \\ = \frac{3 \pm \sqrt{23} }{8} \\ \\ = \frac{3 \pm4.79}{8}$

Either,

$\frac{3 + 4.79}{8} \\ \\ = \frac{7.79}{8} \\ \\ = 0.97$

Or,

$\frac{3 - 4.79}{8} \\ \\ = \frac{ - 1.79}{8} \\ \\ = - 0.23$

$\boxed{ \huge \frak \red{brainlysamurai}}$