NO LINKS!!! Please help me with this graph. Part 6a

[tex]\large{\boxed{ \ g(x) = -\dfrac{7}{4} | x -5| +0 \ }}[/tex]
Absolute value of a graph formula:
Identify the vertex : (h, k) = (5, 0)
Take two points : (5, 0), (9, -7)
[tex]\sf Find \ slope \ (a) : \sf \ \dfrac{y_2 - y_1}{x_2- x_1} \ = \ \dfrac{-7-0}{9-5} \ = \ -\dfrac{7}{4}[/tex]
Join the variables together: [tex]\bf g(x) = - \dfrac{7}{4} | x -5| +0[/tex]
Answer:
[tex]f(x) = -\dfrac{7}{4}|x-5|+0 [/tex]
Step-by-step explanation:
The function in the coordinate Plane is an absolute value function . Consider the parent function
[tex]f(x) = |x| [/tex]
Recall the properties of transformation
From the inspection of the graph,It has moved to right by 5 units, Thus
[tex]f(x - 5) = |x - 5| [/tex]
Apparently, It has neither shifted up or down, hence
[tex]f(x - 5) +0= |x - 5|+0 [/tex]
Looking at the graph, we can see that it has been reflected vertically. It tells us we have to multiply it by a negative constant
[tex] -a f(x - 5) +0= -a |x - 5| +0[/tex]
take (9,7) to figure out a.
[tex] -a | 9- 5| =7[/tex]
Solving the equation yields:
[tex] \boxed{a = - \frac{7}{4} }[/tex]
hence, our function is [tex]\boxed{f(x) = -\dfrac{7}{4}|x-5|+0} [/tex]