Respuesta :

[tex]~~~~~~4(2x-3)(5x+2) = 0\\\\\implies (2x -3)(5x+2) = 0\\\\\implies 2x -3=0 ~~~~~~\text{or}~~~~~~ 5x +2 = 0\\\\\implies 2x =3 ~~~~~~~~~~~\text{or}~~~~~~ 5x = -2\\\\\implies x = \dfrac 32 ~~~~~~~~~~~~ \text{or}~~~~~~ x = -\dfrac 25\\\\\text{Hence,}~ x = \dfrac 32, ~ x = -\dfrac 25[/tex]

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