Question

Please help me
Which equation has the same solutions as x²+6x-7=0 ?
A) (x+3)²=2
B) (x-3)²=2
C) (x-3)²=16
D) (x+3)²=16

Answer 1

Answer:

$D)~(x+3)^2 = 16$

Step-by-step explanation:

$~~~~~~x^2 +6x -7 = 0\\\\\implies x^2+6x = 7\\\\\implies x^2 +2 \cdot 3 \cdot x +3^2 -3^2 = 7\\\\\implies x^2 +2 \cdot 3 \cdot x+3^2 = 7+3^2\\\\\implies (x+3)^2 = 7+9\\\\\implies (x+3)^2 = 16$